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12-28
备考GRE数学我们应该知道些什么呢?出国留学网GRE栏目为大家带来“GRE数学算数类重点试题附答案”，希望能帮到大家哦。
1.In each of the years 1983 and 1984, the total number of automobiles sold in the United States was 1.2 million more than in the previous year.
Percent increase in the number of automobiles sold in 1983 over 1982
Percent increase in the number of automobiles sold in 1984 over 1983
答案：A
2.In how many of the integers between 1 and 100 does the digit 5 occur exactly once?
A.10
B.18
C.19
D.20
E.21
答案：B
3.A school district has 1989 computers, which is approximately one computer for every 68.6 students. Of the following, which is the closest approximation, in thousands, of the number of students in the school district?
A.30
B.120
C.140
D.160
E.200
答案：C
4.If the sum of five consecutive even integers is 70, what is the value of the GREatest of the five integers.
A.12
B.14
C.18
D.20
E.22
答案：C
5.The sum of the first 50 positive integers is 1275. What is the sum of the integers from 51 to 100, inclusive?
A.2525
B.2550
C.325
D.3775
E.5050
答案：D
6.The numbers in a table are arranged in 10 rows and 4 columns su...
11-23
为了帮助大家更好的备考GRE，出国留学网GRE栏目为大家整理了“GRE数学每日一练”，希望对大家有所帮助哦!
The figure above shows the dimensions of a semicircular cross section of a one-way tunnel. The single traffic lane is 12 feet wide and is equidistant from the sides of the tunnel. If vehicles must clear the top of the tunnel by at least foot when they are inside the traffic lane, what should be the limit on the height of vehicles that are allowed to use the tunnel?
A. 5 ft
B. 7 ft
C. 8 ft
D. 9 ft
E. 10 ft
题目翻译：直径为 20 ft 的半圆形交通隧道，行车道在隧道中央，宽 12 ft。要求过往车辆距隧道顶部最近处不能少于 1 ft，下列多高的车应该被禁止通行?
解答：题中已知这个半圆形的直径是20ft，也就是说半径是10ft。已知行车道在路中间并且宽12ft，也就是在圆心两侧各占6ft。根据这两个条件可以构造出直角三角形并利用勾股定理进行计算，得出限高7.2ft。选 CDE
考点：对于几何计算知识与勾股定理的考察。
难点：对于题意的转化。
GRE数学栏目推荐：
11-07
很多考生觉得GRE考试有用难度，但只要我们能好好备考，好好准备，相信许多考生都能取得好的成绩。出国留学网GRE栏目为您整理GRE数学算术类模拟试题及答案，希望能有所帮助哦!
1.At College C there are from 2 to 4 introductory philosophy classes each semester, and each of these classes has from 20 to 30 students enrolled. If one semester 10 percent of the students enrolled in introductory philosophy failed, what is the GREatest possible number who failed?
A.12
B.10
C.8
D.6
E.3
答案：A
2.In each of the years 1983 and 1984, the total number of automobiles sold in the United States was 1.2 million more than in the previous year.
Percent increase in the number of automobiles sold in 1983 over 1982
Percent increase in the number of automobiles sold in 1984 over 1983
答案：A
3.A school district has 1989 computers, which is approximately one computer for every 68.6 students. Of the following, which is the closest approximation, in thousands, of the number of students in the school district?
A.30
B.120
C.140
D.160
E.200
答案：C
4.If the sum of five consecutive even integers is 70, what is the value of the GREatest of the five integers.
A.12
B.14
C.18
D.20
E.22
答案：C
5.The sum of the first 50 positive integers is 1275. What is the sum of the integers from 51 to 100, inclusive?
A.2525
B.2550
C....
1.A,B,C,D,E,F排在1,2,3,4,5,6六个位置上,问A不在1, B不在2, C不在3的情况下,共有多少种排法?
(A) 720
(B) 450
(C) 180
(D) 216
(E) 320
2.一直线L过点A(5,0), B(0,2), 坐标原点为O, 点P(X,Y)为三角形OAB中一点, 问:Y
(A) 1/4
(B) 3/8
(C) 1/2
(D) 5/8
(E) 3/4
3.In an insurance company, each policy has a paper record and an electric record.For those policies having incorrect paper record, 60% also having incorrect electric record; For policies having incorrect electric record, 75% also having incorrect paper record.3% of all policies have both incorrect paper and incorrect electric records.If we randomly pick out one policy,what’s the probability that the one having both correct paper and correct electric records?
(A) 0.80
(B) 0.94
(C) 0.75
(D) 0.88
(E) 0.92
4.If Bob can do a job in 20 days and Jane can do the job in 30 days, they work together to do this job and in this period, Bob stop work for 2.5 days and Jane stop work for x days, and the job be finished for 14 days, what is x?
(A) 1.6
(B) 3.2
(C) 1.5
(D) 1.25
(E) 1.15
5.The probability of A is 60% and the probability of B is 50%, what is the most possible probability that neither A nor B would happen?
(A) 0.80
(B) 0.40
(C) 0.75
(D) 0.55
(E) 0.68
6.There are 1200 respo...
1. 从1,2,3,4,5,6,7,8,9中选出三个数字组成一个三位数,这个三位数的digits中有两个相同,另一个digit与其它两个都不同,问共有多少个这样的三位数?
(A) 72
(B) 144
(C) 180
(D) 216
(E) 54
2.符合 X^2+Y^2<=100的整数解共有多少对?
3.A box contains 100 balls, numbered from 1 to 100.If three balls are selected at random and with replacement from the box,what is the probability that the sum of the three numbers on the balls selected from the box will be odd?
(A) 1/4
(B) 3/8
(C) 1/2
(D) 5/8
(E) 3/4
4.Right triangle PQR is to be constructed in the xy-plane so that the right angle is at P and PR is parrallel to the x-axis.The x-and y-coordinates of P,Q,and Rare to be integers that satisfy the inequalities -4<=x<=5,6<=y<=16,how many different triangles with these properties could be constructed?
(A) 110
(B) 1100
(C) 9900
(D) 10000
(E) 12100
5.(0-9) 要组成三位电话号码,第一位不能是0或1,三位数中相邻两位不能为同一数.(e.g.227 not acceptable, but 272 acceptable),求可以组成多少个这样的电话号码?
参考答案：
1.解：因为三个数中两个数相同，所以从9个数中取出两个的可能性为，三个数中那个不同的数和可能位置为3个，取出的两个数哪个做不同的数的可能性为两种
2.解：本题的意为一个半径为10的圆中的整数对有多少对。首先，(0，0)是一种特殊情况，另四个坐标轴上各有10对解，共41对，对1至7之间的数字而言，任一对均满足条件，则对，对于8，满足条件的有1，2，3，4，5，6六个数，则：
6×2×4=48对解
对于9，满足条件的有1，2，3，4四个数，则：
4×2×4=32
所以总数为41+196+48+32=317对解。
3.解：本题因为奇数和偶数个数相同，和也只有两种方式，所以三个数的和为奇数的可能性为1/2。也可以考虑从这100个...
1.A,B,C,D,E五个人的薪水的median是20000,range不超过50000,其中A,B,C的薪水分别是20000, 40000, 50000,问五个人薪水的平均值可能是多少?
(A) 20000
(B) 32000
(C) 18000
(D) 23000
(E) 31000
2. 一个样本在一个标准方差内的概率是0.68,两个标准方差内的概率是0.95. 一样本,mean=18.6,标准方差是6,求:该样本在6.6-12.6内占多少?
(A) 0
(B) 0.68
(C) 0.27
(D) 0.36
(E) 0.135
3. 一组数平均值9,标准方差2,另外一组数平均值3,标准方差1,问第一组数在(5,11)中的数占总数的比例和第二组数在(1,4)中的数占总数的比例哪个大?
4. 有100个人都对A,B两个人进行评价,每个人只有两种选择,即好或不好,说A不好的有59个,说B不好的有65个,问:同时说AB都好的人数和35比较,哪个大?
5. 两个集合: A=[-1,-2,-3,-4] B=[-2,3,4,5],问B的A次方有多大的概率是正数?
(A) 0
(B) 0.5
(C) 0.625
(D) 0.875
(E) 0.135
参考答案
1.解： median为20000，range为50000，则本题剩下两数的最小值为0，0，最大值为 20000，2000，则平均值最小值为：(0+0+20000+40000+50000)/5 =22000。平均最大值为： (20000+20000+20000+40000+50000)/5=30000。所以五人薪水平均值应在 22000和30000之间。
2.解：本题应加入限制条件：应在正态分布中，否则无解。
Weight指平均值，6.6-12.6 指 -2个方差与 -1个方差之间的概率，所以算发为：(0.95-0.68)/2=0.135
3.解：本题同上题，需在正态分布中讨论，(5，11)中的数是1.5个方差中的数，同样(1，4)中的数也是1.5个方差中的数，所以两组数占总数的比例一样大。
4.解：这种交集的题目列个哥看起来更清楚。所以说AB好的更大交集的35，最小交集为0，所以本题无法判断。
5.解：B的A次方一共有16个，其中只有-2的-1次方和-3次方是负数，所以正数是14个，所以14/16=7/8
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